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0.900 mol of KCl are present in 1000mL of KCl
x mol in 200 mL
x = 200*0.900/1000
x = 0.18 mol of KCl
Moles = Mass/Mr
Mass = Moles*Mr
= 0.18* 74.5
= 13.4 g
x mol in 200 mL
x = 200*0.900/1000
x = 0.18 mol of KCl
Moles = Mass/Mr
Mass = Moles*Mr
= 0.18* 74.5
= 13.4 g
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