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What Is The Theorem Of Compound Probability?

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    The probability of occurrence of the event A as well as B is given by the product of (unconditional) probability of A and conditional probability of B, assuming that A has actually occurred, i.e.

    Probability of (A and B) = Probability of A X Conditional Probability of B, assuming A

    In symbolic form, P(AB) = P(A).P(B|A)

    This is also known as Multiplication Theorem.

    Proof: Suppose that a random experiment has n mutually exclusive, exhaustive and equally likely outcomes, among which m cases are favourable to an event A. So, the unconditional probability of A is

    P(A) = m / n

    Out of these m cases, let m1 cases be favourable to another event B also; i.e. the number of cases favourable to A as well as B is m1. Hence, by the classical definition of probability,

    P(AB) = m1 / n

    It may be noticed that once event A is known to have actually occurred, the occurrence of B as well is limited to only m1 cases out of m (in which A occurs). So, the conditional probability of B, assuming that A has already occurred, is

    P(B|A) = m1 / m

    We find that, m1/n = (m/n).(m1/m)

    i.e. P(AB) = P(A).P(B|A)
    0 0

    Sudipa_sarkar 

    answered 3 years ago

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