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Can You Use The Discriminant To Determine The Number Of Real Solutions Of The Equation? 7 + 5z2 = 2z 1 2 No Real Solutions
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asked 6 months ago
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1 Answer
Rearrange the equation so that it becomes: 5zsquare - 2z + 7
The discriminant is supposed to be = bsquare - 4ac
So the discriminant for this one becomes= (-2)square - 4(5)(7)
= 4 - 140
&nbs
p; &n
bsp;
&nbs
p; = -136
Now the answer is negative which means it is less than zero, and this implies that there are no real roots.
answered 6 months ago
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