How Many Numbers Between 100 And 1000 Can Be Formed With The Digits 2 3 4 0 8 9?
Answer given is 100. Can you please explain how? Or is it 105, 200
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there are total 900 numbers between 100 and 1000 so from 0 100 101 110 200 202 220 300 303 330 400 440 500 505 550 600 606 660 700 707 770 800 808 880 900 909 990 30 from 2 102 112 122 132 142 152 162 172 182 192 200 plus do same with 3 4 8 9 61 from 3 61 from 4 61 from 8 61 from 9 61 answer is 335
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Using the given digits and constraints, we are required to count the ways we can make 3-digit numbers that do not begin with 0.
There are 5 (not 6) ways to choose the first (100s) digit. (choosing 0 is not allowed)
There are 5 remaining digits to choose from for the second (10s) digit.
There are 4 remaining digits to choose from for the third (1s) digit.
5*5*4 = 100 ways to choose the three digits.
There are 5 (not 6) ways to choose the first (100s) digit. (choosing 0 is not allowed)
There are 5 remaining digits to choose from for the second (10s) digit.
There are 4 remaining digits to choose from for the third (1s) digit.
5*5*4 = 100 ways to choose the three digits.
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