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    Using Cramer's Rule, Solve Following System Of Linear Equations. X+2y=7 3x-4y=-9 Can You Help?

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    m_mirza

    x + 2y =7
    3x -4y = -9

    A= 1 2
    3 -4
    !A!=(1)(-4)-(2)(3)
    =-10
    A1=7 2
    -9 -4

    !A1!=7*(-4)+(2)(9)
    =-28+18
    =-10
    A2 =1 7
    3 -9
    !A2!=(-9)(1)-(7)(3)
    =-9-21
    =-30

    X1=!A1! /!A!
    =-10/-10
    =1
    X2=!A2!/!A!
    =-30/-10
    =3
    X1=1 & X2=3 ANS.

    answered 2 years ago   

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      nutkhut86

      X+2y =7, 3x-4y =9

      1. X+2y=7
      2. 3x-4y=9

      4x-2y=16
      2(2x-y) =2(8)

      2x-y=8

      2x=y+8


      x= y+8
      2

      Now put the value of x into 2,
      3x-4y=9

      3(y+8) =9
      2

      1 [(3y+24) =9] (multiply buy 2)
      2

      3y =9-24

      3y=-15

      y=- 5/2

      Put this value of y in x= y+8
      2

      x= -5/2+8
      2

      So the answer is x=3

      answered 2 years ago   

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