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    What Is The Solution To The Quadratic Equation?

    Ax^2+bx+c=o, solve for x Show your steps and a small explanation

    asked 1 year ago

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    2 Answers


    Given
    ax 2 + bx + c = 0


    1. Divide all terms by a -->
    x 2 + (b / a) x + c / a = 0


    2. Subtract c / a from both sides -->
    x 2 + (b / a) x + c / a - c / a = - c / a


    3. Simplify -->
    x 2 + (b / a) x = - c / a


    4. Add (b / 2a) 2 to both sides -->
    x 2 + (b / a) x + (b / 2a) 2 = - c / a + (b / 2a) 2


    5. Complete the square -->
    [ x + (b / 2a) ] 2 = - c / a + (b / 2a) 2


    6. Group the two terms on the right side of the equation -->
    [ x + (b / 2a) ] 2 = [ b 2 - 4a c ] / ( 4a2 )


    7. Solve by taking the square root -->
    x + (b / 2a) = ± sqrt { [ b 2 - 4a c ] / ( 4a2 ) }


    8. Solve for x to obtain two solutions -->
    x = - b / 2a ± sqrt { [ b 2 - 4a c ] / ( 4a2 ) }


    --> The term sqrt { [ b 2 - 4a c ] / ( 4a2 ) } may be written
    sqrt { [ b 2 - 4a c ] / ( 4a2 ) } = sqrt(b 2 - 4a c) / 2 | a |


    --> Since 2 | a | = 2a when a > 0 and 2 | a | = -2a when a < 0, -->
    solution 1 -- > x = [ -b + sqrt( b 2 - 4a c ) ] / 2 a -->

    Solution 2 --> x = [ -b - sqrt( b 2 - 4a c ) ] / 2 a

    answered 1 year ago   

    This was entered with line breaks. I do not know what happened. Sorry.

    comment made by Jnawrocki 1 year ago    Report

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      In mathematics, the quadratic equation is a polynomial equation of the second degree. The general form is ax2 + bx + c = 0
      The letters a, b, and c are called as coefficients: The quadratic coefficient a is the coefficient of x2, linear coefficient b is the coefficient of x, and c is the called constant coefficient and also called the free term.
      For more information, see the link below:
      en.wikipedia.org

      answered 1 year ago   

      what is the solution for X, not the coeficients

      comment made by Diaflor 1 year ago    Report

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