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I Need Help Understanding The Type Of Problems That Go Like This; Find Two Numbers Whose Product Is 18 And Whose Sum Is 9?

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    Usually, the answer to such a problem is a pair of integers. That means you can find the answer by examining the factors of the product value, 18 in this case.
      18 = 1*18 = 2*9 = 3*6
    You want the factors whose sum is 9.
      1+18 = 19
      2 + 9 = 11
      3 + 6 = 9
    The numbers you seek are 3 and 6.

    The general way to solve a problem like this is to assign a variable to each number and write two equations. Let the numbers be represented by x and y.
      x*y = 18    (two numbers have a product of 18)
      x + y = 9    (the same two numbers have a sum of 9)
    We can solve the second equation for y.
      y = 9 - x    (subtract x from both sides of the second equation above)
    With this expression for y, we can make a substitution into the first equation.
      x*(9 - x) = 18
    This equation can be rearranged into the standard form for quadratics.
      x*9 - x*x = 18    (use the distributive property)
      9x = x^2 + 18    (add x^2 to both sides)
      x^2 - 9x + 18 = 0    (subtract 9x from both sides, swap sides to put the 0 on the right)
    This quadratic can be solved several ways. If you don't have a clue about the factors of 18, you can use the quadratic formula. Otherwise you can solve by factoring or by completing the square.
    Factoring
      (x - 3)(x - 6) = 0    (this method is essentially equivalent to the one we started with--finding factors of 18 that add to 9)
      x = {3, 6}
    Completing the square
      x^2 - 9x + 18 + 2.25 = 2.25    (add a constant so that the constant term on the left is (9/2)^2)
      (x - 4.5)^2 = (1.5)^2    (factor showing the squares)
      x - 4.5 = ±1.5    (square root of both sides)
      x = 4.5 ± 1.5 = {3, 6}    (add 4.5 to both sides and evaluate)
    Quadratic formula
      For a*x^2 + b*x + c = 0, the solution is
      x = (-b ±√(b^2 - 4*a*c))/(2*a)
      = (-(-9) ±√((-9)^2 - 4*1*18))/(2*1)
      = (9±√(81-72))/2
      x = (9±3)/2 = {3, 6}
    Each of the three methods above yields a value for x. You will note that if x is chosen as one of them, then y = 9-x will be the other one.
    0 0

    Oddman  

    answered 3 weeks ago

         
         

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