Can You Find The Y Values For X=-2,-1,0,1,2,3 If Y =x^-x-2?

Y=x^-x-2

For x=-2
y=(-2)^-(-2)-2
=(-2)^2-2
=4-2

=2

For x=-1

y=(-1)^-(-1)-2

=(-1)^1-2

=-1-2



=-3


For x=0

y=(0)^-(0)-2

=(0)^0-2

=1-2

=-1



For x=1

y=(1)^-(1)-2

=(1)^-1-2
=(1/(1)^1) -2

=1-2



=-1


For x=2

y=(2)^-(2)-2

=(2)^-2-2

=(1/(2)^2)-2

=1/4-2
=(1-8)/4

=-7/4


For x=3

y=(3)^-(3)-2

=(3)^-3-2

=(1/(3)^3)-2
=1/27-2
=1-54/27

=-53/27


if equation is Y=x^2-x-2 then please check this answer.