How Many Moles Of Water Would Be Produced From 10 Moles Of Butane Burned In An Excess Of Oxygen?
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Butane is an organic compound and its molecular formula is CH3CH2CH2CH3 or C4H10. Butane is also categorized as a hydrocarbon because it consists of carbon and hydrogen atoms. When butane is burned in excess of oxygen it forms carbon dioxide and water.
C4H10 + 13/2O2 --------- > 4CO2 + 5H2O
Five moles of water are produced from one mole of butane.
Multiply the ionic equation by 10, we get
10C4H10 + 10*13/2O2 --------- > 10*4CO2 + 10*5H2O
10C4H10 + 65O2 --------- > 40CO2 + 50H2O
So, 50 moles of water are produced from ten moles of butane burned in an excess of oxygen.
C4H10 + 13/2O2 --------- > 4CO2 + 5H2O
Five moles of water are produced from one mole of butane.
Multiply the ionic equation by 10, we get
10C4H10 + 10*13/2O2 --------- > 10*4CO2 + 10*5H2O
10C4H10 + 65O2 --------- > 40CO2 + 50H2O
So, 50 moles of water are produced from ten moles of butane burned in an excess of oxygen.
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