Can Someone Show Me How They Figure Out This Problem? ∛8 Answer: 2 What Is The Steps Please?

Good Evening:
Thanks for your reply
I am bit confuse here, I am sorry can back in more steps for me. I am not asking you to do my work. I am trying to understand the formula better. I am learning all the algebra language
∛8 You wrote 8^(1/3) = e^(Ln[8]/3)
Do you mean 8 is the exponents? 1/3 is in parentheses,so this is
(0.33) ̅
So are you 8 is the exponents of 33? If this is the case? How do you fiqure exponents ?
Now I do not understand this language
= e^(Ln[8]/3)
How do I fiqure?

The notation x^n means x raised to the power of n. X^(1/3) is x raised to the 1/3 power, which is the same as the cube root of x. I find it easier and faster to write 8^(1/3) than to search for the symbol for cube root and insert that into the text.
Ln[8] means the natural logarithm of 8. Many calculators have both the base-10 logarithm (Log[x]) and the natural logarithm (Ln[x]) functions available. For purposes of taking cube roots, any logarithm will do.

Once you have the logarithm of the number, you divide it by 3. That is Ln[8]/3 in the formula. The result is the logarithm of the cube root of 8. Now, you take the antilog of this number. You do that by raising the logarithm base (e, in the case of natural logarithms; 10 in the case of base-10 logarithms) to the power of this number. On a calculator, the key is often labeled e^x (e with a superscript of x), or 10^x (10 with a superscript of x).