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How Do You Solve This Quadratic Formula 6x^2+3x-18=0 Please Show The Work?

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    Divide both sides of the equation by 3.
      2x^2 + x - 6 = 0

    This can be solved by factoring. We suspect that the factors of 2 (coefficient of x^2 term) and 6 (constant term) can be combined in a way that will give 1 (coefficient of x term).
      2x^2 + 4x - 3x - 6 = 0    (divide the x term into a sum of products)
      2x(x+2) - 3(x+2) = 0    (first factoring stage)
      (2x-3)(x+2) = 0    (second factoring stage)

    Now, we have the factored equation. We can determine the roots by setting each of the factors to zero.
      2x-3 = 0
      x = 3/2

      x+2 = 0
      x = -2

    The solutions are x = -2, x = 3/2.
    0 0

    Oddman 

    answered 7 months ago

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