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3x2+19x-14=0
where, a = 3, b = 19 and c = -14
Quadratic formula is as follows:
x = -b + √b^2 - 4ac
2a
x = -19 + √19^2 - 4*3(-14)
2*3
x = -19 + √38 + 168
6
x = -19 + √206
6
Therefore, solution set is {-19 + √206 , -19 - √206}
6 6
where, a = 3, b = 19 and c = -14
Quadratic formula is as follows:
x = -b + √b^2 - 4ac
2a
x = -19 + √19^2 - 4*3(-14)
2*3
x = -19 + √38 + 168
6
x = -19 + √206
6
Therefore, solution set is {-19 + √206 , -19 - √206}
6 6
1
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