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What Magnitude Of F2 Causes The Net Torque On The Rod To Be Zero?

In The Figure, Force F2 Acts Half As Far From The Pivot As F1.

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    General Torque= r*f sin(theta)

    T2= r*F2 Sin(90)o


    As distance of F1 is twice of F2 from pivot


    T1=2r*F1 Sin(45)o


    Net torque=0


    T1-T2=0

    T1=T2 2r*F1

    Sin(45)o = r*F2 Sin(90)o


    2*20*0.707=F2

    F2=28.28N
    1 0

    Amber22 

    answered 1 year ago

    Thank you for helping me. God Bless You!
    Report
    Toosh

    Toosh

    commented 1 year ago

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