What Magnitude Of F2 Causes The Net Torque On The Rod To Be Zero?
In The Figure, Force F2 Acts Half As Far From The Pivot As F1.
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General Torque= r*f sin(theta)
T2= r*F2 Sin(90)o
As distance of F1 is twice of F2 from pivot
T1=2r*F1 Sin(45)o
Net torque=0
T1-T2=0
T1=T2 2r*F1
Sin(45)o = r*F2 Sin(90)o
2*20*0.707=F2
F2=28.28N
T2= r*F2 Sin(90)o
As distance of F1 is twice of F2 from pivot
T1=2r*F1 Sin(45)o
Net torque=0
T1-T2=0
T1=T2 2r*F1
Sin(45)o = r*F2 Sin(90)o
2*20*0.707=F2
F2=28.28N
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