Solve The Following Quadratic Equations Using Any Method You Prefer, (i Would Like Too Use The Quadratic Formula) 1. 6x^2 - 8x + 5 And 2. 3x^2= 4x + 8 Which Equals Out Too -3x^2 +4x +8 Right ? I Can Work It Out, I Just Get Stuck At The Same Point.

1. 6x^2 - 8x + 5  is an expression, not an equation. Perhaps you mean
  6x^2 - 8x + 5 = 0
  This is ax^2 + bx + c = 0 where a=6, b=-8, c=5.
  The quadratic formula says
  x = (-b±√(b^2-4ac))/(2a)
  = (-(-8)±√((-8)^2 - 4(6)(5)))/(2*6)
  = (8±√(64-120))/12    (simplify radical terms)
  = (8±√-56)/12    (compute radical value, recognize we have 2 complex roots)
  = (8±2i√14)/12    (simplify the radical)
  = 2/3 + (i/6)√14  or  2/3 - (i/6)√14    (simplify the roots)
  ≈ 0.6667 ± 0.6236i    (converted to approximate decimal values)

2. 3x^2 = 4x + 8
  3x^2 - 4x - 8 = 0    (rearranged to standard form with a > 0 (my preference))
  x = (4 ±√(4^2 - 4(3)(-8)))/(2*3)    (coefficients plugged into quadratic formula)
  = (4 ±√(16+96))/6    (simplify the radical terms)
  = (4 ±√112)/6    (simplify the radical)
  = (4 ±4√7)/6    (simplify the radical)
  = (2/3)(1±√7)    (factor out 4/6 = 2/3)
  ≈ {2.4305, -1.0972}    (approximate decimal values)