What's The Maximum Concentration Of 4x/3x^2+27?
The percent of concentration K of a drug in the bloodstream x hours after the drug is administered is given by K(x)=4x divided by 3x^2 +27 a. Find the time at which the concentration is a maximum. B. Find the maximum concentration
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Function k(x)= 4x/3x^2+27 . In order to find max and mini percentage of concentration of drug in blood stream, we have to differentiate the function and equate it to zero
derivative of the function k(x) is :
(4/(3x^2+27))-(24x^2/(3x^2+27)^2)=0
the maximal occurs at(3,0.22)
0.22 % of concentration of drug in 3 hours
the minimal occurs (-3,-0.22)
derivative of the function k(x) is :
(4/(3x^2+27))-(24x^2/(3x^2+27)^2)=0
the maximal occurs at(3,0.22)
0.22 % of concentration of drug in 3 hours
the minimal occurs (-3,-0.22)
0
0
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