Can You Solve It By Using The Quadratic Formula X^2 - 3x = 7x - 2?
Please solve this problem
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X^2 - 3x = 7x - 2
using the same logic as earlier
we get
X^2 - 3x - 7x = -2
that is x^2 - 10x = -2
the factors for this are
(x)(x-10) = -2
so we get
either x = -2 or
x - 10 = -2
that is x = 8
so x is either = -2 or x = 8
using the same logic as earlier
we get
X^2 - 3x - 7x = -2
that is x^2 - 10x = -2
the factors for this are
(x)(x-10) = -2
so we get
either x = -2 or
x - 10 = -2
that is x = 8
so x is either = -2 or x = 8
1
0
The answers given here are wrong. If you check the value of 8, you'll find that 8^2 - 3*8 is not equal to 7*8 - 2. (40 is not equal to 54).
If you want to use the Quadratic formula, (-b +/- sqrt(b^2 - 4ac) )/2a, to solve it, you would do so as follows;
To use the quadratic formula, you would first find the coefficients a, b, and c of the formula x^2 -10x + 2 = 0. That gives you values of a, b, c to be 1, -10, and 2 respectively. Then plug them into the quadratic formula and solve.
If you want to use the Quadratic formula, (-b +/- sqrt(b^2 - 4ac) )/2a, to solve it, you would do so as follows;
To use the quadratic formula, you would first find the coefficients a, b, and c of the formula x^2 -10x + 2 = 0. That gives you values of a, b, c to be 1, -10, and 2 respectively. Then plug them into the quadratic formula and solve.
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