How Many Grams Of Butyl Alcohol (C4H9OH) Are In A 2500 ML Solution Which Is 2.22M?

Total Number of moles in the solution = 2.50L x 2.22mol/L or

 M = 5.55 mol.

Every mol of C4H9OH has 4x12.0 +9.0+16.0+1.0 g. = 74 g/mol.

Total number of grams = 5.55 mol x 74.0g/mol = 410.7g.

so 411g is the answer

Add Comment

Report