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    What Is The Solution Set Of 256 Equal To X Times The Square Root Of Logarithm Of X To The Base 2?

    asked 2 years ago

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    The Question is as follows
    256 = (log2(x))^1/2
    Taking Square root at both sides
    16 = log2(x)
    Now taking anti log
    e^16 = x
    which is Approx equals to
    8886110.52

    answered 1 year ago   

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