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(f3 + 2f2) (-f - 2)
For factorizing it, let suppose,
(f3 + 2f2) (-f - 2) = 0
-f4 - 2f3 + 2f3 - 4f2 = 0
-f4 - 4f2 = 0
Multiply expression by negative sign on both sides,
f4 + 4f2 = 0
f2 (f4 + 2) = 0
Now, f2 = 0
f = 0
f2 +2 = 0
f = (- 2)1/2
f = (- 2)1/2i
For factorizing it, let suppose,
(f3 + 2f2) (-f - 2) = 0
-f4 - 2f3 + 2f3 - 4f2 = 0
-f4 - 4f2 = 0
Multiply expression by negative sign on both sides,
f4 + 4f2 = 0
f2 (f4 + 2) = 0
Now, f2 = 0
f = 0
f2 +2 = 0
f = (- 2)1/2
f = (- 2)1/2i
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The second factor is already pretty simple. The only way to make it simpler is to factor out the -1. -f-2=-(f+2).
The first factor has a common factor of f2. So we get f3 + 2f2 = f2(f + 2).
Putting it all together, we have two factors of f + 2. So the answer is
-f2(f + 2)2
The first factor has a common factor of f2. So we get f3 + 2f2 = f2(f + 2).
Putting it all together, we have two factors of f + 2. So the answer is
-f2(f + 2)2
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0
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