2/(n2+3)^1/2 , Any Idea?
The nth term of the sequence is given; check whether the sequence is convergent or divergent.
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Each term of the series whose nth term is 2/sqrt[n^2+3] is equal to or larger than each term of the series 1/n, the sum of which does not converge. Therefore, the series in question does not have a sum that converges.
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