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How Can We Find The Angle Between Two Curves?

If Y^2=4ax And X^2=4ay Then Find Angle Between These Two Curves?

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    The angle between two curves at the point of intersection is the angle b/w their tangents:
    Tan (theta) =m2-m1/ 1-m1m2   where m1 and m2 are the slopes
    Y2=4ax               x2=4ay
    x=y2/4ax
    Put in x2=4ay
    Y4/16a2 =4ay
    By solving we get;
    y=0 and   y=4a


    When   y=0             then x=0      we get (0, 0)
    When   y=4a           then x=4a    we get (4a, 4a)

    Y2=4ax
    Differentiate it
    2ydy/dx=4a
    dy/dx=2a/y

    at point (4a, 4a)
    m1=2a/4a=1/2

    x2=4ay
    y=1/4a x2
    dy/dx= x/2a
    at the point (4a, 4a)
    m2=4a/2a= 2
    let theta be the angle b/w them
    tan(theta)=m2-m1/1-m1m2
    tan(theta)=3/4
    theta=tan-1(3/2)
    www.regentsprep.org
    1 0

    Sehri 

    answered 2 years ago

      Jnawrocki 

      answered 2 years ago

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