What Is Total Work Done In A Gravitational Field When A Ball Is Thrown Vertically Upward?

Consider a ball of mass "m" is thrown vertically upward through a height "h". Then the ball moves downward under the action of gravity. The total work done by the gravity along the closed path is given as;
Total work done=work done in going upward + work done in moving downward
                                = F.h + F.h
                                =mghcos180 + mghcos 0
                                = -mgh+mgh
Total work done=0
Force of gravity is a conservative force and field is conservative field.
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When a ball is thrown vertically upward then displacement and gravitational force are anti_parallel i.e making an angle 180..as w=f.dcostheta and as cos180=_1.......so workdone is negative and as displacement covered is height so d=h and force acting antiparallel to weight is approx = to weight little more than it...so formula becomes w= -mgh....i hope dat answers ur question..:)