A) set up an equation for the perimeter involving only L, the length of the rectangle. B) Solve this equation algebraically to find the length of the rectangle. Find the width as well. Answer: Length__________, Width__________ How do you solve this problem?
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The length of the triangle is 15 inches and so the width of the triangle is 10 inches. The perimeter will then be 2(15+10)=50 So the answer is
L=15
W=10
answered 12 months ago
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Given: W= L-5
& P = 50
Solution:
P = 2L + 2W = 50
2L + 2(L-5) = 50 since W=L-5
2L +2L - 10 = 50
4L = 60 divide both sides by 4, so,
L = 15, answer substituting L to W= L-5
Therefore,
W = 10 ^^ answer
answered 11 months ago
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