Can You Find The Product [4p+3/2q][3p-3/4q]?

First get the denominator same so get -
2( 4p+3)     ( 3p-3)
  -------    x  ----------
    4q          &nb... 4q

= ( 8p+6)       ( 3p-3)

    -------     x ----------

         4q          4q

=   12p^2 -6p-18            6(2p^2 - p - 3)
     -----------------  =     -------------------
       ... 4q          &nb... 4q

=3   (2p-3)(p+1)
  -------------------
   2q

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You can mult the lower term first because it's more simple then the equation will be [ (3p-3)*(4p+3)/8q^2 ]
then take every term individually from one bracket and mult. by the two terms of the second brackets
the equation will be (12p^2+9p-12p-9)/8q^2
at last
(12p^2-3p-9)/8q^2
may this help you

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