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The quadratic equation ax2+bx+c = 0 has solutions
x = (-b ±√(b2 - 4ac))/(2a)
x2 -3x -3 = 5 (your equation)
x2 -3x -8 = 0 (subtract 5 from both sides to put into standard form)
In your equation, a=1, b=-3, c=-8
x = (-(-3) ±√((-3)2 - 4*1*(-8)))/(2*1)
= (3 ±√(9+32))/2
x = (3±√41)/2
x ≈ {4.7, -1.7}
x = (-b ±√(b2 - 4ac))/(2a)
x2 -3x -3 = 5 (your equation)
x2 -3x -8 = 0 (subtract 5 from both sides to put into standard form)
In your equation, a=1, b=-3, c=-8
x = (-(-3) ±√((-3)2 - 4*1*(-8)))/(2*1)
= (3 ±√(9+32))/2
x = (3±√41)/2
x ≈ {4.7, -1.7}
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