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asked 3 months ago
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I suppose "vertex form" for your function would be
F(x) = a(x-h)^2 + k
where (h, k) is the vertex.
We can rewrite your equation as
F(x) = 2(x^2 - 6x) + 17
We can add and subtract 18 to get this into vertex form
F(x) = 2(x^2 - 6x + 9) + 17 - 18
F(x) = 2(x-3)^2 - 1 for vertex = (3, -1)
F(x) = a(x-h)^2 + k
where (h, k) is the vertex.
We can rewrite your equation as
F(x) = 2(x^2 - 6x) + 17
We can add and subtract 18 to get this into vertex form
F(x) = 2(x^2 - 6x + 9) + 17 - 18
F(x) = 2(x-3)^2 - 1 for vertex = (3, -1)
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