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Can You Solve This 6(x-2)-3(x+5)=2(5x-2)?

I am new to this site and asking help for algebra homework.

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    Evaluate the parentheses:

    6(x-2) = 6x - 12
    3(x +5) = 3x + 15
    2(5x-2) = 10x - 4

    Therefore:

    6x - 12 - 3x - 15 = 10x - 4

    Group up the x's onto one side, and numbers on the other:

    6x - 3x - 10x = -4 +15 + 12

    -7x = 23

    x=-3.285714 or -(3 + 2/7)
    1 0

    Madbiker 

    answered 3 years ago

      been a while but this is what i get...

      6(x-2)– 3(x +5)=2(5x-2)
      (6x-12)-(3x+15)=10x-4
      6x-12-3x-15=10x-4
      6x-3x-10x=12+15-4
      -7x=23
      x=23/-7
      x=-3.286
      1 0

      Stephen 

      answered 3 years ago

        Well it's really easy all you have to do is that multiply the numbers outside the bracket with the numbers inside the bracket and bring all the numbers at one side of the equation.
        0 0

        Kahfi 

        answered 3 years ago

        Kahfi - why don't you show/demonstrate to maridee the solving process here? Perhaps she is just learning algebra?
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        Amore01

        Amore01

        commented 3 years ago

        6(x-2)-3(x+5)=2(5x-2)
        (6x-12)-(3x-15)=10x-4
        6x-3x-10x-12-15+4=0
        -7x-23=0
        -7x=23
        x=23/-7
        You just divide it!!!!!!
        0 0

        Ashlee 

        answered 2 years ago

        15-(3-4y)=2(y+2)
        0 0

        Erowe 

        answered 2 years ago

          F(x) = x3 + 5x2 - 3x - 15
          0 0
          Guest

          Guest 

          answered 8 months ago

          Solve x2 - 6x-13 = 0 by completing the square
          0 0
          Guest

          Guest 

          answered 8 months ago

          Guest

          Guest 

          answered 3 months ago

          You simply do -
          6 * x = 6x
          6 * -2 = -12
          -3 * x = -3x
          -3 * 5 = -15
          2 *5x = 10x
          2 * -2= -4
          and now put the answers together -
          6x - 12 - 3x - 15 = 10x - 4
          0 1
          Guest

          Guest 

          answered 6 months ago

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