What Is The Density In G/mL Of A Cube With Each Edge 0.0393m And Mass Of 0.171kg?

Start with the mass divided by the volume, then convert the units to ones you like.

.171 kg/(.0393 m)³ = (.171 kg)(1000 g/kg)/((.0393 m)(100 cm/m))³
= 171 g/(39.3 cm)³ = 171/60,698 g/cm3 = .00282 g/((cm³)(1 ml/1 cm³))
= .00282 g/ml

Density of a substance is defined as D=M/V or mass/volume and is calculated as follows:

the volume of the cube is obtained by cubing the edge
=(0.093_m)³ =10^-4_m³=100_cm³

the mass of 0.171kg=171_g

conversion needed is 1_cm³=1_ml

therefore the density of the cube=171_g/100_cm³=1.71_g/cm³ x 1cm³/1ml x 1_ml/1_cm³=1.71_g/cm³

Oddman's answer is off by a few decimal places, because he multiplied 0.0393 by 100 and got 39.3. It should be 3.93. So the volume of the cube in cc is 3.93³ = 60.7 (I rounded to 3 significant figures because the numbers we are given have 3 significant figures). The mass in grams he gave is correct, 171. So the density is 171/60.7 = 2.82 g/mL