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Solve By Factoring: 2x^2-3x=x^2+18

Solve problem by factoring

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    2x^2-3x=x^2+18

    2x^2 - x^2 -3x -18 = 0

    x^2 -3x -18 = 0

    x^2 - 6x + 3x -18 = 0

    x (x-6) +3 (x-6) =0

    (x+3) (x-6) =0

    either

    x+3 =0   or   x-6 =0

    x= -3          x =  6  >>>> answer

    0 0

    Jannifer  

    answered 2 years ago

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