Simplify The Following Expression : (3i Square Root Of 6)^2 I Dont Understand How Im Suppose To Work Out This Equation?
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As with the square of any other product, the result is the product of the squares.
(3i√6)^2 = (3^2)(i^2)((√6)^2) = 9*6*i^2 = 54i^2
Of course you know that
i = √(-1), so i^2 = -1
Then
54i^2 = -54
(3i√6)^2 = (3^2)(i^2)((√6)^2) = 9*6*i^2 = 54i^2
Of course you know that
i = √(-1), so i^2 = -1
Then
54i^2 = -54
(3i√6)^2 = -54
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