Home EducationSubjectsAlgebra Subscribe to RSS

Solve 6x^2+3x-18=0 Using The Quadratic Formula?

How do you solve this problem?

Answer Question

4 Answers - Sort by: Date | Rating

    If you need the answer then it will be (X=3/4, -2).

    From equation a=6, b=3 and c=-18 and then put these values in quadratic formula, and then simplify this equation.

    I hope you will get the answer very easily.
    0 0

    Sfahad 

    answered 2 years ago

      Here is your quadratic equation :
      6x2 + 3x – 18 = 0
      therefore 6x(square)+12x-9x-18=0
      6x(x+2)-9(x+2)=0
      (6x-9)(x+2) = 0
      therefore 6x-9 =0  and  x+2=0
      therefore x=9/6 and x=-2

      so the correct answer is x = {3/2, -2}


      rough work

      18 * 6 = 108
      now can we take 12 * 9
      like +12 and -9, which will sum up and  give +3{between} and the product 108{ product of first and the last 18 * 6 }
      0 0

      Eimraan 

      answered 2 years ago

        Solve 6x^2 + 3x - 18 = 0 using the quadratic formula.
        0 0
        Guest

        Guest 

        answered 4 months ago

        Here is the solution:
        6x2 + 3x - 18 = 0
        6x2 +12x - 9x - 18= 0
        6x(x+2) -9(x+2) = 0
        (6x -9)(x+2)= 0
        x = -2 is one answer
        x= 9/6 or 2/3 is second answer
        0 1

        Aicha 

        answered 2 years ago

        why didn't you divide the original equation by 3 at first? that's why you're second solution is wrong.
        Report
        Junewhee

        Junewhee

        commented 1 year ago

        More

           
           

          Ask a Question via Twitter

          Send a question to @askblurtit and we will publish it online and send you a reply everytime you receive an answer.

          Blurtit Store

          Get T-shirts, hoodies, caps and more at the Blurtit store

          Blurtit International