x2 + (28 - x)2 = 202 Let x be the length of one side. Therefore the length of the other side is 28 – x.
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Length of hypotenuse=20cm
The length of other two sides=28cm
let the two sides are x & y
X+y=28cm
As it is a right angle triangle so according to Pythagoras
theorem;
20^2=x^2+y^2
Putting y=28-x in above equation
X^2+ (28-x)^2 =400
2X^2-56x+384=0
X=16cm ; x=12cm
When x=16cm then y=28-16=12cm
When x=12cm then y=28-12=16cm
answered 5 months ago
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