Can You Solve 2x^2+7x=5?

Let's solve the quadratic equation:
    2x^2+7x = 5
First we need to put the equation in the form:
    ax^2 + bx + c = 0
For this, we set the equation to equal 0, and arrange the terms from the highest exponent to the lowest:
    2x^2+7x-5 = 0
We have:
    a=2 b=7 c=-5
We can now apply the quadratic formula:
    x = ( -b ± √(b²-4ac) ) / 2a
We find two solutions:
    x=0.60849528301415 or x=-4.1084952830142

OR

First we need to put the equation in the form:
  ax^2 + bx + c = 0
For this, we set the equation to equal 0, and arrange the terms from the highest exponent to the lowest:
  2x^2+7x-5 = 0
We have:
  a=2  b=7  c=-5
We can now apply the quadratic formula:
  x = ( -b ± v(b²-4ac) ) / 2a
We find two solutions:
  x=0.60849528301415  or  x=-4.1084952830142