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3x2+19x-14=0
a = 3, b = 19, c = -14
x = {-b + (b2 - 4ac)1/2}/2a
x = {-19 + (192 - 4(3)(-14)1/2}/2(3)
x = {-19 + (361 + 168)1/2}/6
x = {-19 + (529)1/2}/6
x = {-19 + (529)1/2}/6 and x = {-19 - (529)1/2}/6
a = 3, b = 19, c = -14
x = {-b + (b2 - 4ac)1/2}/2a
x = {-19 + (192 - 4(3)(-14)1/2}/2(3)
x = {-19 + (361 + 168)1/2}/6
x = {-19 + (529)1/2}/6
x = {-19 + (529)1/2}/6 and x = {-19 - (529)1/2}/6
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See also the other instance of this question by Annastar1 at http://www.blurtit.com/q948463.html
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