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asked 3 months ago
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The length of BC is half the length of AC, and equal to the length of AB.
BC = (7y - 30) = (1/2)(3y - 5)
2(7y - 30) = 3y - 5 (multiply the equation involving y by 2)
14y - 60 = 3y - 5 (use the distributive property to eliminate parentheses)
11y = 55 (add 60-3y to both sides)
y = 55/11 = 5
BC = 7y - 30 = 7*5 - 30 = 35 - 30 = 5
BC = (7y - 30) = (1/2)(3y - 5)
2(7y - 30) = 3y - 5 (multiply the equation involving y by 2)
14y - 60 = 3y - 5 (use the distributive property to eliminate parentheses)
11y = 55 (add 60-3y to both sides)
y = 55/11 = 5
BC = 7y - 30 = 7*5 - 30 = 35 - 30 = 5
The length of BC is 5.
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