What Is The Quadratic Equation Given The Vertex Of (1,4) And Passes Through The Point (-1,-8)?
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asked 5 months ago
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The vertex form of a quadratic equation is
(y - k) = a(x - h)^2
You have (h, k) = (1, 4), so the equation is
y - 4 = a(x - 1)^2
We want to choose a so that (x, y) = (-1, -8) satisfies the equation.
(-8) - 4 = a((-1) - 1)^2
-12 = 4a (evaluate)
-3 = a (divide both sides by 4)
(y - k) = a(x - h)^2
You have (h, k) = (1, 4), so the equation is
y - 4 = a(x - 1)^2
We want to choose a so that (x, y) = (-1, -8) satisfies the equation.
(-8) - 4 = a((-1) - 1)^2
-12 = 4a (evaluate)
-3 = a (divide both sides by 4)
The quadratic is y-4 = -3(x-1)^2, or y = -3x^2 + 6x + 1
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