(n-3)!/(n-1)! Any Idea?
The nth term of the sequence is given; check whether the sequence is convergent or divergent.
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The series sum seems to converge to 1 for n=3..Infinity. (The sum up to and including the term for n seems to be 1-1/(n-1). For n<=2, the terms of the series don't seem to be defined:
(n-3)!/(n-1)! = (n-3)!/((n-1)(n-2)(n-3)!)
= 1/((n-1)(n-2)) for n>=3
For n=1 or 2, the denominator is 0, so the series term is 1/0 = undefined.
(n-3)!/(n-1)! = (n-3)!/((n-1)(n-2)(n-3)!)
= 1/((n-1)(n-2)) for n>=3
For n=1 or 2, the denominator is 0, so the series term is 1/0 = undefined.
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