What Are The Steps Used To Solve The Algebraic Equation? 4x+3(x-8)-x=6
I don't understand how to do this without knowing the steps. So if you can please help i might understand how to do it.
Guest
asked 2 years ago
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4x+3(x-8)-x=6
Multiply 3 with (x-8)
4x + 3x - 24 -x =6
Add and subtract like terms
4x + 3x -x =6 +24
6x = 30
Dividing both sides by 6 you will get
6x/6= 30/6
x= 5 >>> answer
Multiply 3 with (x-8)
4x + 3x - 24 -x =6
Add and subtract like terms
4x + 3x -x =6 +24
6x = 30
Dividing both sides by 6 you will get
6x/6= 30/6
x= 5 >>> answer
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First solve (4x+3)(x-8)
(4x2-29x-24)-x-6=0
4x2-30x-30=0
2X2-15x-15=0
using quadratic equation
x=(-root(345)/4)+ (15/4)
x=(+root(345)/4)+ (15/4)
(4x2-29x-24)-x-6=0
4x2-30x-30=0
2X2-15x-15=0
using quadratic equation
x=(-root(345)/4)+ (15/4)
x=(+root(345)/4)+ (15/4)
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4x+3(x-8)-x=6
Step1:
Solve : 4x +3(x-8)-x = ?
4x +3(x-8)-x = 4x +3x-24 -x
= 6x -24
step 2 :
4x+3(x-8)-x=6 ------> 6x -24=6
6x = 24 +6
x = (24+6)/6
x = 30/6
x= 5
Step1:
Solve : 4x +3(x-8)-x = ?
4x +3(x-8)-x = 4x +3x-24 -x
= 6x -24
step 2 :
4x+3(x-8)-x=6 ------> 6x -24=6
6x = 24 +6
x = (24+6)/6
x = 30/6
x= 5
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0
Guest
answered 8 months ago
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