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Each mole of sodium sulfate (Na2SO4) has 2 moles of sodium ions (Na+). We figured this out from the formula which shows 2 sodium atoms (Na2...).
Now the molarity of the solution of sodium sulfate is 0.220M. This means that the number of moles of sodium sulfate in one liter is 0.220. Therefore, 3.9L solution would have the following number of moles:
0.220 x 3.9 = 0.858
So, the number of moles of sodium sulfate in 3.9l solution is 0.858 moles. Since the number of moles of sodium is twice that of sodium sulfate, the number of moles of sodium would be:
0.858 x 2 = 1.716 moles
Therefore, there are 1.716 moles of sodium in 3.9L of 0.22M sodium sulfate.
Now the molarity of the solution of sodium sulfate is 0.220M. This means that the number of moles of sodium sulfate in one liter is 0.220. Therefore, 3.9L solution would have the following number of moles:
0.220 x 3.9 = 0.858
So, the number of moles of sodium sulfate in 3.9l solution is 0.858 moles. Since the number of moles of sodium is twice that of sodium sulfate, the number of moles of sodium would be:
0.858 x 2 = 1.716 moles
Therefore, there are 1.716 moles of sodium in 3.9L of 0.22M sodium sulfate.
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