Can Someone Show Me How To Solve This Problem?

The absolute value of x is -x if x<0 and +x if x>=0. Thus, the problem can be written two different ways, each one having a condition.

1) 5 - (3-y) > 4, where (3-y)>=0
  2 + y > 4    (collect terms on the left)
  y > 2    (subtract 2 from both sides)
now look at the condition
  3-y>=0
  3 >= y    (add y to both sides)
so, the whole solution is ...
  2 < y <= 3

2)  5 - (-(3-y)) > 4, where (3-y)<0
  8 - y > 4    (collect terms on the left)
  4 - y > 0    (subtract 4 from both sides)
  4 > y    (add y to both sides)
now look a the condition
  3-y < 0
  3 < y    (add y to both sides)
so, the other whole solution is ...
  3 < y < 4

Taken together, these solutions say that
  2 < y < 4

Add Comment

Report

First you can find the absolute value of the 3-y. The absolute value of a number is that same number only positive. So you'll have
5-(3+y)>4 now the negative sign infront of the parenthesis will change all the signs inside the parenthesis.
5-3-y>4
2-y>4 whatever you do on one side of an equation you can do on the other. So now you can add (-2) to both sides to get:
-y>2 now you have
y<-2
I hope this helps you.
 

Add Comment

Report