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Solve 5x+4y=12.(b)When graphed this equation would be a line.By examining your answer to part a, what is the slope and y- intercept of this line?Slope= , y-intercept=.(C) using your answer from part a,find the corresponding value of y when x=16. #2 Calculate the value of the discriminant of x^2+4X+4=0.Exam the sign of the discriminant in part a, how many x-intercepts would the graph of y=x^2+4x+4 have ? Why?
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You can graph the given equation by assuming a range of values for x (say from -3 to +3). Substitute each value in the given equation to calculate the corresponding value for y.
The given equation is in the form y = mx + c. Therefore, the
slope = -5/4 and y-intercept = 3.
To calculate the value of y when x = 16
5(16) + 4y = 12
4y = 12-80
4y = -68
y = -17
Discriminant = b^2 - 4ac
= 16 - 4(1)(4)
=0
The y=x^2+4x+4 would have 2 x-intercepts
The given equation is in the form y = mx + c. Therefore, the
slope = -5/4 and y-intercept = 3.
To calculate the value of y when x = 16
5(16) + 4y = 12
4y = 12-80
4y = -68
y = -17
Discriminant = b^2 - 4ac
= 16 - 4(1)(4)
=0
The y=x^2+4x+4 would have 2 x-intercepts
0
0
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