How Do I Calculate How Many Atoms Are Present In 18.80 G Of Fluorine?
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You start off by converting everything to mloles.
18.80g F 1 mole F 6.022x10(23 power) F
----------- x ------------- x ----------------------------- =
1 19.0g F 1 mole F
answer: 5.959x10(23 power) atoms F
skip the second step if 18.80g was what you took from the periodic table.
18.80g F 1 mole F 6.022x10(23 power) F
----------- x ------------- x ----------------------------- =
1 19.0g F 1 mole F
answer: 5.959x10(23 power) atoms F
skip the second step if 18.80g was what you took from the periodic table.
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