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What Is The Smallest Number In A GP Whose Sum Is 38 And Product 1728?
asked 2 years ago
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the answer given is wrong. there are only two unknown involved. one is the first term and the second is the common ratio. let three numbers be in gp they are a, ar, ar^2.
then the product is 1728 implies (ar)^3 = 12^3 . this implies ar = 12 or a = 12/r. substitute in the sum a(1+r + r^2) = 38 gives the numbers 8,12,18 or 18,12,8. note that the value of r is 3/2.
comment made by Veeraa1729 6 months ago
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