Where Can I Get Help For This Algebra Problem?

Try to write it out, as you read it.

The sum of two digits of a two digit number is 11;
Let's take the first digit to be A, and the second digit to be B;
So we write an equation as follows: A*10 + B = 11,   since we're most likely dealing with base 10 and the first number is actually a single digit with a place multiplier.

Now we write out the second equation, just like it sounds;
If the digits are reversed, the new number is 45 more than the original number.
So let's use B for the first number and A for the second,
and write B*10 + A = 11 + 45

Now we have two equations, and two unknowns.  Substitute and solve for one unknown, and then the other.

I'll check back and see how you're doing.

Hahahaha I get it!!!!!!! 56 its 56. 5+6=11 reverse them, 65

Try righting the sum out as you read it. And learn stuff the same on Internet or out if books