Peter Kelly answered question 3/16/2011 Iron Has BCC Crystal Structure With Lattice Parameter Of 0.142 :calculate Atomic Diameter? The Lattice constant is a=(2*atomic radius)/sqrt(3) if a=0.142 then radius = (sqrt(3)*a)/2 or r = (1.73*0.142)/2 = 0.123 nm so the Diameter is 2r or 0.246 nm
