answered question
A Honey Bee Flies In Circles Around A Flower. If The Velocity Of The Bee Is 670 Cm/s And The Radius Of The Circular Path Is 2.0 Cm, What Is The Centripetal Acceleration Of The Honey Bee?
Velocity of Honey Bee = 670 cm/s ,  Radius of Circular Path = 2 cm , Acceleration of Honey bee = velocity^2 / Radius  =  670^2/2 = 448900/2 = 224450 cm/s^2 = 2244.5 m/s^2 = 2.2 km/s^2.
answered question
The Bottom Of A Box Has A Surface Area Of 58.8 Cm2. The Mass Of The Box Is 12.0 Kg. Acceleration Due To Gravity At Sea Level Is 9.80 M/s2. What Is The Pressure Exerted By The Box Where It Rests?
Area of bottom of the box is  (A) = 58.8 cm^2 = 58.8x10^-4 m^2 , Mass of the box (M)= 12 kg ,  Acceleration due to gravity (g) = 9.8 m/s^2 ... Formula for Pressure is = Force/Area.   Therefore Pressure exerted by the box= 12 x 9.8 / 58.8 x 10^-4 = 2x 10^4 N/m^2..