Deepak Suwalka
Deepak Suwalka answered

Given root of polynomial function x=∛28

g(2)=x3 -28=0

Applying Newton's method

x_(n+1) = x_n - (g(x_n)) / (g'(x_n))

For c₁ ⇒ c₁ = c₀ - (g(c₀)) / (g'(c₀))

Thus, c₀ =3

So, g'(3)=27

g(3)=27-28=-1

c₁ = (3-(-1)) / (27) = (81+1) / (27)

c₁ = (82)/(27)

Deepak Suwalka
Deepak Suwalka answered

To find 'c', solve f'(x)=0

⇒ (x² − 1) × 1 + 2x(x − 2) = 0

⇒ x²− 1 + 2x² − 4x = 0

⇒ 3x2 − 4x−1 = 0

It's a quadratic equation so, solve it using quadratic formula

⇒ [4±√16-(4)(3)(-1)] / (2(3))

⇒x = (2±√7)/(3)

⇒x = (2+√7)/(3) and x = (2-√7)/(3)

x = (2+ √7)/(3) = 1.55 ∈(1,2]

x … Read more

Deepak Suwalka
Deepak Suwalka answered Anonymous' question

geometric return = ⁿ√{(1+r₁) × (1+r₂) × ...} - 1

Where, r = rate of return

n = number of periods

For 1st yr, rate of return = r₁ = 5% = 0.05

For 2nd yr, rate of return = r₂ = -30% = -0.3

Number of years = 2

geometric return = √{(1 + 0.05)(1 - 0.3)}-1= √{(1.05) (0.7)}-1

= -0.143

Geometric … Read more

Deepak Suwalka
Deepak Suwalka answered

Let advance Tickets = A

door tickets = D

Make equations according to the problem

A + D = 120.....(1)

10A + 15D = $1390....(2)

Multiplying eq(1) by 10 and subtracting from eq(2) we get

D = 38(number of tichets at door)

Put value of D in eq(1) we get-

A + 38 = 120

A = 82(number of tichets were purchased in advance)

Goaty McSheepson
Goaty McSheepson answered

Bob is 20 years older than Ben. In 10 years, Bob will be twice as old as Ben. How old is each now?If Bob is 20 years older than Ben, then he was 20 years old when Ben was born.

If, in ten years, Bob will be twice as old as Ben, then we must consider … Read more

Deepak Suwalka
Deepak Suwalka answered

16 + (28/2) - (6 /10) - 4 × 2

Use order of operation, i.e., PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction)

First, simplify parenthesis

= 16 + 14 - 0.6 - 4 × 2

Now, multiplication

= 16 + 14 - 0.6 - 8

Similarly, apply addition and subtraction

= 30 - 0.6 - 8

= 21.4